Allow to pass only one file name to unlink-services

This commit is contained in:
Jerome Petazzoni
2015-09-23 20:06:07 -07:00
parent 8c3ef01dd3
commit 676bbd02fe

View File

@@ -3,7 +3,11 @@
import sys
import yaml
input_file, output_file = sys.argv[1:3]
# You can specify 1 or 2 parameters:
# - with 1 parameter, the same file will be used for in and out
# - with 2 parameters, the 1st is the input, the 2nd the output
input_file = sys.argv[1]
output_file = sys.argv[:1]
stack = yaml.load(open(input_file))