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Allow to use COMPOSE_FILE env var in scripts

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This commit is contained in:
Jerome Petazzoni
2015-10-05 08:50:48 -07:00
parent ecc5a3eafe
commit 33d29248bb
4 changed files with 26 additions and 6 deletions
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3
build-tag-push.py
View File

@@ -65,4 +65,5 @@ for service_name, popen_object in push_operations.items():
with open(output_file, "w") as f:
yaml.safe_dump(stack, f, default_flow_style=False)
print("Wrote new compose file: {}".format(output_file))
print("Wrote new compose file.")
print("COMPOSE_FILE={}".format(output_file))

3
configure-ambassadors.py
View File

@@ -5,7 +5,8 @@ import subprocess
import sys
import yaml
stack = yaml.load(open(sys.argv[1]))
compose_file = os.environ.get("COMPOSE_FILE") or sys.argv[1]
stack = yaml.load(open(compose_file))
project_name = os.path.basename(os.path.realpath("."))

3
create-ambassadors.py
View File

@@ -5,7 +5,8 @@ import subprocess
import sys
import yaml
stack = yaml.load(open(sys.argv[1]))
compose_file = os.environ.get("COMPOSE_FILE") or sys.argv[1]
stack = yaml.load(open(compose_file))
project_name = os.path.basename(os.path.realpath("."))

23
link-to-ambassadors.py
View File

@@ -1,13 +1,30 @@
#!/usr/bin/env python
import os
import sys
import yaml
# You can specify 1 or 2 parameters:
# You can specify up to 2 parameters:
# - with 0 parameter, we will look for the COMPOSE_FILE env var
# - with 1 parameter, the same file will be used for in and out
# - with 2 parameters, the 1st is the input, the 2nd the output
input_file = sys.argv[1]
output_file = sys.argv[-1]
if len(sys.argv)==1:
if "COMPOSE_FILE" not in os.environ:
print("Please specify 1 or 2 file names, or set COMPOSE_FILE.")
sys.exit(1)
compose_file = os.environ["COMPOSE_FILE"]
if compose_file == "docker-compose.yml":
print("Refusing to operate directly on docker-compose.yml.")
print("Specify it on the command-line if that's what you want.")
sys.exit(1)
input_file, output_file = compose_file, compose_file
elif len(sys.argv)==2:
input_file, output_file = sys.argv[1], sys.argv[1]
elif len(sys.argv)==3:
input_file, output_file = sys.argv[1], sys.argv[2]
else:
print("Too many arguments. Please specify up to 2 file names.")
sys.exit(1)
stack = yaml.load(open(input_file))