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91ecdaba4e
Right now, sending a sigint will start a graceful shutdown, which can take quite a while. By calling stop() in the signal handler it unregisters the handler so that a subsequent sigint received during a graceful shutdown will kill the process immediately. Signed-off-by: Ian Fox <code@whatthefox.dev>
32 lines
646 B
Go
32 lines
646 B
Go
package main
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import (
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"context"
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"os"
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"os/signal"
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"syscall"
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"github.com/kubescape/go-logger"
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"github.com/kubescape/kubescape/v3/cmd"
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)
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func main() {
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// Capture interrupt signal
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ctx, stop := signal.NotifyContext(context.Background(), os.Interrupt, syscall.SIGTERM)
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defer stop()
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// Handle interrupt signal
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go func() {
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<-ctx.Done()
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// Perform cleanup or graceful shutdown here
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logger.L().StopError("Received interrupt signal, exiting...")
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// Clear the signal handler so that a second interrupt signal shuts down immediately
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stop()
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}()
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if err := cmd.Execute(ctx); err != nil {
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stop()
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logger.L().Fatal(err.Error())
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}
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}
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